因式分解題目1(10分)

2008-07-16 5:12 am
Please Answer all the question:

MC:
1)it's given that ax=ay and cx=dy are factors of Ax²+Bxy+Cy² and A=ac.Which of the following equal Ax²+Bxy+Cy² ?
A.(a+c)x+(b+d)y
B.(ax+by)(cx+dy)
C.acx+bdy
D.(ac+bd)xy

2)Factorize 8a+4b
A.8(a+b)
B.4(2a+b)
C.8ab
D.32ab

3)Which of the following is a factor of 3xy+2y+6x+4?
A.y
B.3x
C.y=2
D.x+3

4)Which of the following can be written as 6mn+3m² after expansion?
A.3m(2n+m)
B.3m(n+3m)
C.3m(26m)
D.6m(n+3m)

Short Question:
5)Factorize the following polynomials.
A.)2x+6xy
B.)ab+a²
C.)2u²v+uv-10uv²
D.)12xy²z+6x²z+10yz²
E.)8s-8st+5-5t
F.)2ab-6a+5b-15
G.)26+14s-13t-7st
H.)5m(n-3)+m²(3-n)
I.)2x^4-x³+2x-4x²
J.)6cd(3-d)-3(2d-6)

Longer question:
6)
A.)Factiorize the polynomial 2y-4-x(3y-6).
B.)Using the result of part (A),factorize the polynomial 2y-4+6(2y+1)(2-y).
更新1:

Extra MC: 1)Which of the following polynomial can be written in the form of(ax+b)²? I.x²+2x+1 II.x²-2x+1 III.x²+x+1 A.)I only B.)III only C.)I & II only D.)I,II,and III

更新2:

2)Which of the following is/are (a)factor(s) of 25(a+b)²-4(a-b)² I.a=b II.3a+7b III.(7a+3b)² A.)I only B.)II Only C.)I nd III only D.I,II and III

更新3:

更正部份: 1)it's given that ax+ay and cx+dy are factors of Ax²+Bxy+Cy² and A=ac.Which of the following equal Ax²+Bxy+Cy² ? A.(a+c)x+(b+d)y B.(ax+by)(cx+dy) C.acx+bdy D.(ac+bd)xy 3)Which of the following is a factor of 3xy+2y+6x+4? A.y B.3x C.y+2 D.x+3

更新4:

更正部份: 5) I.)2x^4-x³+2x-4x², 2x^4即是2x的4次方!

回答 (2)

2008-07-16 6:39 am
✔ 最佳答案
答案錯晒, 唔識就咪答, 教錯人

2008-07-15 22:39:38 補充:
MC:
1)it's given that ax=ay and cx=dy are factors of Ax²+Bxy+Cy² and A=ac.Which of the following equal Ax²+Bxy+Cy² ?
A.(a+c)x+(b+d)y
B.(ax+by)(cx+dy)
C.acx+bdy
D.(ac+bd)xy



1)條題目根本唔啱, 因無講B及C到底是什么, 你列錯式
2) 答案是B
3) ABCD都不是答案, 答案應爲y+2 或3x+2, 見以下計算方法
factorization
3xy+2y+6x+4
= y(3x + 2) + 2(3x+2)
= (y+2)(3x+2)

4)答案是A

5)Factorize the following polynomials.
A.)2x+6xy
= 2x(1+3y)

B.)ab+a²
= a(a+b)

C.)2u²v+uv-10uv²
=uv(2u+1-5v)

D.)12xy²z+6x²z+10yz²
=2z(6xy²+3x²+5yz)
= 6xz(2y²+x)+10yz²
= 2z[3x(2y²+x)+5yz] 這條不太肯定

E.)8s-8st+5-5t
=8s(1-t)+5(1-t)
=(8s+5)(1-t)

F.)2ab-6a+5b-15
=2a(b-3)+5(b-3)
= (2a+5)(b-3)

G.)26+14s-13t-7st
= 13(2-t)+7s(2-t)
= (13+7s)(2-t)

H.)5m(n-3)+m²(3-n)
= 5m(n-3)-m²(n-3)
= m(5-m)(n-3)

I.)2x^4-x³+2x-4x²=^符號根本打錯, 不能計

J.)6cd(3-d)-3(2d-6)
= 6cd(3-d)+6(3-d)
=6(cd+1)(3-d)

Longer question:
6)
A.)Factiorize the polynomial 2y-4-x(3y-6).
= 2(y-2)-3x(y-2)
= (2-3x)(y-2)

B.)Using the result of part (A),factorize the polynomial 2y-4+6(2y+1)(2-y).
=[2-6(2y+1) ](y-2) using result of part A
= (2-12y-6)(y-2)
=-(4+12y)(y-2)
=4(1+3y)(2-y)
參考: 自己
2008-07-16 6:17 am
1) 2)b 3)c 4)a
5A)2x(1+3y) B)a(b+a) C)uv(2u+1-10v) D)2z(6xy^2+3x^2+5z)
E)8s(1-t)+5(1-t) F)2a(b-3)+5(b-3) G)2(13+7s)-t(13+7s)
(8s+5)(1-t) (2a+5)(b-3) (13+7s)(2-t)
H)(n-3)(5m-m^2)
l)x(2x^3-x^2+2-4x)
J)6cd(3-d)-3{2(d-3)}
(d-3)(6cd-6)


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