Let tanA= 3/2
(a) By finding the values of sinA and cos A first, evaluate (sinA-cosA)/cosA
Hint: Use tanA= sinA/cosA and square both sides.
(b) Find the value of (sinA-cosA)/cosA without finding the values of sinA and cosA first.
(c) Which method is quicker, the one in (a) or the one in (b)?
Show steps,please
Trigonometric identities
2008-07-15 9:45 pm
回答 (1)
2008-07-15 10:46 pm
✔ 最佳答案
The answer is as follows:圖片參考：http://i277.photobucket.com/albums/kk75/uncle_michael/080715_mat01a.jpg?t=1216104300
圖片參考：http://i277.photobucket.com/albums/kk75/uncle_michael/080715_mat01b.jpg?t=1216104370
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