2(x^2-1)+Ax=(x+B)(Cx-1)
**x^2是x的2次
=是恆等於
問一條數(恆等式)急急急急急...
2008-07-14 3:10 am
回答 (1)
2008-07-14 3:25 am
✔ 最佳答案
2(x^2-1)+Ax = (x+B)(Cx-1) 2x^2+Ax-2 = Cx^2+BCx-x-B
2x^2+Ax-2 = Cx^2+(BC-1)x-B
Therefore B=2 , C=2 and
A=(BC-1)
A=(2*2-1)=3
Hence 2(x^2-1)+3x = (x+2)(2x-1)
收錄日期: 2021-04-13 15:48:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080713000051KK02221