solve this quadratic?

9x^2 = 50

so x^2 = 50/9

x = √(50/9)

x = ± (√50)/3

x = ± 2.357022604

or ± 5√2
.......-------.....if you prefer Radicals/Surds
..........3

Nothing complicated about this

♫ ………. ;-)

Divide both sides by 9

9x^2/9 = 50/9

x^2 = sqrt(50/9)

sqrt(9) = 3

x = sqrt(50)/3 and x = -sqrt(50)/3

9x^2 = 50 isolate x^2
x^2 = 50/9 take square roots and simplify.
x=√(50/9) or x=-√(50/9)
x=(5√2)/3 or x=-(5√2)/3

9x^2=50

x^2=50/9
x=sqrt 50/9

x=sqrt 50 / 3
x=sqrt 25*sqrt 2/ 3

5 sqrt 2/ 3

9x^2 = 50
x^2 = 50/9
x = ±√(50/9)
x = ±(√50)/3

x² = 50 / 9
x = ± √ (50/9)
x = ± (5/3)√2

first simplify the equation
x^2=50/9, then take the roots
x= 5/3 sqrt of 2, -5/3 sqrt of 2

so first is to make a to side...
a constant and variable side...

so...
x^2=50/9
so.. to get the squared on the x we need to raise the both equation by the power of 1/2 so..

x=+/-(50/9)^1/2
so...
we have x=2.357 and x= -2.357
we had to answers for the value of x..

9x^2 = 50
x^2 = 50/9
x = (square root 50)/(square root 9)
x = (square root 25 x 2)/3
x=(plus or minus)(5 sqrt 2)/3

I'll use * for the multiplication symbol.

9x^2 -50 = 0 sqrt(50) = sqrt(25 * 2) = sqrt(25) * sqrt(2) = 5sqrt(2)

The equation factors as follows: (3x -5sqrt(2)) * (3x + 5sqrt(2))

Solutions: (5/3) * 5sqrt(2) and -(5/3) * sqrt(2)

first, divide each side by 9
x^2 = 50/9
now sqrt each side
x = sqrt(50/9)
there are two answers
5 sqrt(2) / 3
- 5 sqrt(2) / 3