Simplify 2 { [ 3(z-5)+16] - [ 2(3z-3)+1] }= ?

2008-07-12 7:24 am

回答 (7)

2008-07-12 7:30 am
✔ 最佳答案
2 { [3(z - 5) + 16] - [2(3z - 3) + 1] }

2 { [ 3z - 15 + 16] - [6z - 6 + 1] }

2 { [ 3z + 1] - [6z - 5] }

2 { 3z + 1 - 6z + 5 }

2 { -3z + 6 }

-6z + 12

hope this helped!
2016-12-12 5:22 pm
Première answer :Pareil que Brumy : -a million...-2...-3...-4...-5...etc. Deuxième answer : Décolage ! Troisième answer : BOUM !! Quatrième answer : Bonne Année ! Cinquième answer : Partez !! Sixième answer : Rendez vos copies !
2008-07-12 11:53 am
2 { [ 3(z - 5) + 16 ] - [ 2 (3z - 3) + 1 ] }
2 { [ 3z + 1 ] - [ 6z - 5 ] }
2 { 3z + 1 - 6z + 5 }
2 { 6 - 3z }
12 - 6z

It is good to see brackets being used to present a clear, well defined question.
Can but hope answer is correct !
2008-07-12 8:00 am
2{[3(z - 5) + 16] - [2(3z - 3) + 1]}
= 2{[3*z - 3*5 + 16] - [2*3z - 2*3 + 1]}
= 2{[3z - 15 + 16] - [6z - 6 + 1]}
= 2{[3z + 1] - [6z - 5]}
= 2{3z + 1 - 6z + 5}
= 2{3z - 6z + 1 + 5}
= 2{-3z + 6}
= 2*-3z + 2*6
= -6z + 12
2008-07-12 7:39 am
2 { [ 3(z-5)+16] - [ 2(3z-3)+1] }=
=2{3z+1-6z+5}
=-6z+12
=12-6z
2008-07-12 7:31 am
2{(3z+1)-(6z-5)}
2{-3z+6}
-6z+12
2008-07-12 7:30 am
6z + 2 - 12z + 10
6z = 12
z = 2


收錄日期: 2021-05-01 10:48:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080711232433AA3msxv

檢視 Wayback Machine 備份