Please solve 3x^2-4x+1=0?

3x^2 - 4x + 1 = 0
(3x - 1)(x - 1) = 0
x = 1/3 OR x = 1

3x^2 - 4x + 1 = 0
3x^2 - x - 3x + 1 = 0
(3x^2 - x) - (3x - 1) = 0
x(3x - 1) - 1(3x - 1) = 0
(3x - 1)(x - 1) = 0

3x - 1 = 0
3x = 1
x = 1/3

x - 1 = 0
x = 1

∴ x = 1/3 , 1

3x^2 - 4x + 1=0
=> 3x^2 - 3x +x +1=0
=> 3x(x-1) - 1(x-1)=0
=> (x-1) (3x-1)=0
=> x-1=0 or 3x-1=0
=> x=1 or 1/3.......

3x^2 - 4x + 1 = 0
(3x - 1)(x - 1) = 0

x -1 = 0 --------->change sign on one & move to other side
x = 1

3x - 1 = 0 --------->change sign on one & move to other side
3x = 1--------> divided both sdie by 3
x = 1/3

(3x-1)(x-1)

x = 1 and/or 1/3