4y+2y+5-3y=7+1=?

4y + 2y + 5 - 3y = 7 + 1
6y - 3y = 8 - 5
3y = 3
y = 3/3
y = 1

Enless you write your question out properly, the answer is 8.

3y = 3
y = 1

the way you have written out your question, you are suggesting that the value of 4y+2y+5-3y is equal to 7+1 and that you want to know what this is equal to, the answer is 8

4y + 2y + 5 - 3y = 7 + 1

First, combine like terms(the y's and the constant 7 + 1):

3y + 5 = 8

Subtract 5 from each side:

3y = 3

Divide both sides by 3:

y = 1

4y+2y+5-3y=7+1
3y+5=8
3y=8-5
3y=3
y=3/3=1

group them together..

4y+2y-3y = 7+1-5
3y = 3
t = 1

4y+2y+5-3y=8
3y+5=8
3y=3
y=1