25 divide 5 = 2y?

25/5 = 2y
2y = 5
y = 5/2
y = 2.5

25/10 = 2.5

initially, factorise all the quadratic equation; (y^2 ? 4y ? 21)/(y^2 ? 10y + 25)] ÷ [(y^2 + 2y ? 3)/(y^2 ? 6y + 5) is comparable as [ (y-7)(y+3) / (y-5)(y-5) ] ÷ [ (y-a million)(y+3) / (y-5)(y-a million) ] Simplify; [ (y-7)(y+3) / (y-5)(y-5) ] ÷ [ (y-a million)(y+3) / (y-5)(y-a million) ] = [ (y-7)(y+3) / (y-5)(y-5) ] * [ (y-5)(y-a million) / (y-a million)(y+3) ] Now aspects cancel ( can tutor on paper) and the applicable answer turns into; = (y-7) / ( y-5) answer = C

25/5 = 2y
2y = 5
y = 5/2
y = 2.5

25/5=2y
5=2y
y=5/2
y=2.5

2y=5 y=5/2=2 1/2

25 = 10 y
y = 2.5

25/5=2y
5=2y
y=5/2
y=2.5

=25/5
=2 x 5/5
= 2 x 1
= 2

25/5=2y
5=2y
y=5/2