what is 5 x3 = 45x?

5x^3 = 45x
5x^3 - 45x = 0
5x(x^2 - 1) = 0
5x(x+1)(x-1) = 0
x = -1, 0, 1

5x^3 = 45x
x^3 = 9x
x^2 = 9
x = +/- sqrt 9
x = +/- 3

5 x^3=45x
x^3=45x/5
x^3=9x
x^3/x=9
x^2=9
x=+3 or -3

5x³ = 45x
5x³ - 45x = 0
5x (x² - 9) = 0
x = 0 , x = 3 , x = - 3

5x^3 = 45x
5x^2 - 45x = 0
(5x^2 - 45x)/5 = 0
x^2 - 9x = 0
x(x - 9) = 0

x = 0

x - 9 = 0
x = 9

∴ x = 0 , 9

We have 5*3=45x. So:

15=45x.

Now, what is occurring with the 45 and the x? They are being multiplied together, so you need to perform the reverse operation. The reverse operation of multiplication is division, so we need to divide the 45x by 45 to cancel the 45 out and leave us with just x.

So:

15 = (45x)/(45)

But wait, if we perform it to one side of the equation, we must perform it to the other side to keep it equal.
So:

15/45 = 45x/45

The 45 is canceled out of the right side, so we cross the 45 out, and we are left with:

15/45 = x
or
x = 0.3333333 repeating (or 1/3 in fraction form).

5 times 3 =45x

15 =45x

15 divided by 45 = 45x divided by 45

1 divided by 3 = x

x = 1/3