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更新1:
(c) ans is e^(4a) ,(d) ans is 1/2
a-maths!!~
2008-07-11 9:20 pm
As follow As~~
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圖片參考：http://www.photo-host.org/img/007248screenhunter_01_jul._11_13.14.gif
回答 (5)
2008-07-12 2:25 am
✔ 最佳答案
As follows~~~As follows~~~
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2008-07-15 07:12:40 補充：
或許閣下的問題有不清楚的地方，但在意見欄中集合各高手之意見，終於找出c和e的答案。
c part可往:
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim2.jpg
2008-07-15 07:12:55 補充：
d part可往:
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim3.jpg
2008-07-15 07:14:04 補充：
多謝各位高手指點，以上兩part的更正，特別鳴謝飛天魏國大將軍張遼。
參考: Myself~~~
2008-07-15 8:42 am
(c) By L' Hospital rule:
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim2.jpg
(d) 條題目本身有錯: arcsin 的 domain 係 -1 <= x <= 1, 所以個 limit 應該係 tends to zero:
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim3.jpg
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim2.jpg
(d) 條題目本身有錯: arcsin 的 domain 係 -1 <= x <= 1, 所以個 limit 應該係 tends to zero:
http://i117.photobucket.com/albums/o61/billy_hywung/Jul08/Crazylim3.jpg
2008-07-13 2:43 am
我想問
lim (x->0) (arcsinx)/x 都是 1 ?
因為我發覺如果d 的答案是 1/2 的話,那
lim(x->oo) (arcsinx)/2x
= lim (n->0) [arcsin(1/n)]/2(1/n)
= lim (n->0) n[arcsin(1/n)] / 2
= 1/2 ?????/
是= 1/2嗎?
lim (x->0) (arcsinx)/x 都是 1 ?
因為我發覺如果d 的答案是 1/2 的話,那
lim(x->oo) (arcsinx)/2x
= lim (n->0) [arcsin(1/n)]/2(1/n)
= lim (n->0) n[arcsin(1/n)] / 2
= 1/2 ?????/
是= 1/2嗎?
2008-07-12 2:37 am
(b)
Break (2+...+n)/n^2 into 2/n^2 + .... + n/n^2,
trivially, it tends to 0 as N tends to infinity;
However, the whole thing is independent of x,
and will not change no matter how x varies.
Break (2+...+n)/n^2 into 2/n^2 + .... + n/n^2,
trivially, it tends to 0 as N tends to infinity;
However, the whole thing is independent of x,
and will not change no matter how x varies.
2008-07-11 10:42 pm
It should not be Amaths. Amaths doesn't require arcsin and exponential function
收錄日期: 2021-04-23 20:36:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080711000051KK01108