a-maths!!~
回答 (5)
我想問
lim (x->0) (arcsinx)/x 都是 1 ?
因為我發覺如果d 的答案是 1/2 的話,那
lim(x->oo) (arcsinx)/2x
= lim (n->0) [arcsin(1/n)]/2(1/n)
= lim (n->0) n[arcsin(1/n)] / 2
= 1/2 ?????/
是= 1/2嗎?
(b)
Break (2+...+n)/n^2 into 2/n^2 + .... + n/n^2,
trivially, it tends to 0 as N tends to infinity;
However, the whole thing is independent of x,
and will not change no matter how x varies.
It should not be Amaths. Amaths doesn't require arcsin and exponential function
收錄日期: 2021-04-23 20:36:45
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