Solve using the quadratic formula:?

/
z=8+-sqrt(64-24)/6=8+-sqrt40/6=
4+-sqrt10 all over 3

3z^2 - 8z + 2 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 3
b = -8
c = 2

x = [8 ±√(64 - 24)]/6
x = [8 ±√40]/6
x = [8 ±6.32]/6 (approx.)

x = [8 + 6.32]/6
x = 14.32/6
x = 3.58/1.5
x = 179/75

x = [8 - 6.32]/6
x = 1.68/6
x = 168/600
x = 7/25

∴ x = 7/25 , 179/25

z = [ 8 ± √ (64 - 24 ) ] / 6
z = [ 8 ± √ (40) ] / 6
z = [ 8 ± 2√10 ] / 6
z = [ 4 ± √10 ] / 3

ax squared + bx + c = 0

then x = -b + - square root of b squared - 4ac divided by 2a

so 8 +- square root of (-8)squared - 4 (3) (2) divided by 2 x 3

8+- square root of 64-24 divided by 6

8+- square root 40
---------------------------
6

8+- 2 square root of 10
--------------------------------
6

4+- square root of 10
----------------------------
3

quadratic forumla

x = (-b +/- √(b^2 - 4ac))/2a
x = (8 +/- √(64 - 24))/6
x = (8 +/- √40)/6
x = (8 +/- 2√10)/6
x = (4 +/- √10)/3

so
x = (4 - √10)/3, (4 + √10)/3