Dividing Polynomials? This equation helpzzzz??!?

2008-07-10 10:38 am
2x^6-13x^5+75x³+2x²-50/x-5

thanks!

回答 (5)

2008-07-10 10:56 am
✔ 最佳答案
Hi,

The easier way is synthetic division.
..__________________
5)2..-13...0...75..2..0.-50
..___10.-15.-75_0.10..50
...2...-3.-15...0...2.10....0 <=remainder of 0

2....-3.-15....0...2.10 gives the answer:
2x^5 - 3x^4 - 15x³ + 2x + 10 <==ANSWER

I hope that helps!! :-)
2008-07-10 6:09 pm
(2x^6 - 13x^5 + 75x^3 + 2x^2 - 50)/(x - 5)
= (2x^5 - 3x^4 - 15x^3 + 2x + 10)(x - 5)/(x - 5) (cancel out x - 5)
= 2x^5 - 3x^4 - 15x^3 + 2x + 10
2008-07-10 6:03 pm
= 2x^6–13x^5+0x^4+75x³+2x²+0x–50/x – 5
x – 5|2x^6 –13x^5 +75x³ +2x² – 50|2x^5 –3x^4 –15x³ +2x+10
------- 2x^6 – 10x^5
--------------------------------
-------- 0 ---- – 3x^5 + 0x^4
---------------- – 3x^5 + 15x^4
-------------------------------------------
--------------- -- 0 – 15x^4 + 75x³
---------------------- – 15x^4 + 75x³
----------------------------------------------
-------------------------- 0 --------- 0 +2x² + 0x
------------------------------------------ +2x² – 10x
----------------------------------------------------------
------------------------------------------- 0 + 10x – 50
------------------------------------------- 0 + 10x – 50
----------------------------------------------------------------
---------------------------------------------------- 0
---------------------------------------- 0 + 10x – 50
Answer 2x^5 –3x^4 –15x³ +2x+10
----------
2008-07-10 5:58 pm
If you put x = 5 into the numerator you will get 0 indicating that x-5 is a factor of that equation.

Start by writing (x - 5) and the other factor
(x - 5) (.........)
Now you need to get 2x^6 so you need to multiply by 2x^5
(x - 5) (2x^5 ..........) which leaves a -10x^5
Since you need -13x^5 multiply by -3x^4
(x - 5) (2x^5 - 3x^4 ......) which leaves 15x^4
And so on.....

The whole thing:
(x - 5) (2x^5 - 3x^4 - 15x^3 + 2x + 10)
2x^6 - 10x^5 - 3x^5 + 15x^4 - 15x^4 + 75x^3 +2x^2 - 10x + 10x - 50

So the result of the division is:
(2x^5 - 3x^4 - 15x^3 + 2x + 10)
2008-07-10 5:55 pm
To begin, its not any equation. Pl revise its meaning!!!
To divide Nr by x-5 rearrange the terms so that x-5 is a factor.
Thus (2x^6 -10x^5) -(3x^5 - 15x^4) - (15x^4 -75x^4) and so on...
Each bracket has x-5 as a factor.
Try the rest.


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