factor x to the 2 power - 6x + 9?

You probably mean factor the expression x^2 - 6x + 9

x^2 - 6x + 9 = (x-3)^2 = (x-3)(x-3)

x² - 6x + 9 = (x - 3)(x - 3) = (x - 3)²

a^2 - ab + b^2 = (a - b)^2

x^2 - 6x + 9
= x^2 - 3x - 3x + 9
= (x^2 - 3x) - (3x - 9)
= x(x - 3) - 3(x - 3)
= (x - 3)(x - 3)
= (x - 3)^2

You need to find two numbers that multiply to be 9 and add to be -6... It's -3 and -3. So x2 - 6x + 9 = (x - 3)(x - 3)

(x-3)(x-3)= (x-3)^2

(x-3)^2
or
(x-3) (x-3)

it's the same thing

(x-3)(x-3) Is that what you are looking for?>

(-6x+9)at 2 ? (-6x)at 2 +2*(-6x)*9+81=

x² - 6x + 9 = (x - 3)²