-(2x^5/yz^2) times ( y^2z/x^4)?
回答 (6)
2008-07-09 4:26 pm
✔ 最佳答案
-(2x^5/yz^2)(y^2z/x^4)= (-2x^5/yz^2)(y^2z/x^4)
= (-2x^5 * y^2z)/(yz^2 * x^4)
= -2x^5y^2z/x^4yz^2
= (-2/1)(x^5/x^4)(y^2/y)(z/z^2)
= -2(x)(y)(1/z)
= -2xy/z
2008-07-09 11:30 pm
-2xy/z
2008-07-09 11:29 pm
-2xy/z
2008-07-09 11:27 pm
4
2008-07-09 11:23 pm
-(2x^5/yz^2) times ( y^2z/x^4) = -2xy/z
2008-07-09 11:22 pm
-2xy / z
收錄日期: 2021-05-01 10:51:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080709081856AAZqIPr