x^3+5x^2=6x
x^2-3x=10
x(x-2)(x+3)=0
Solve each of the following equations?
2008-07-09 7:31 am
回答 (6)
2008-07-09 7:36 am
✔ 最佳答案
x³ + 5x² = 6xx = 0, 1 and -6
---------------------------
x² - 3x = 10
x = 5, -2
---------------------------
x(x - 2)(x + 3) = 0
x = 0, 2, -3
=================================
I didn't show the working out. I just used my calculator but to get the answer, you can factorise it - it's not too hard. Alternatively, use the quadratic formula (for quadratic equations!)
2016-04-06 12:07 pm
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assuming that V is a typo you would add the x's and have 4x+1=9 then you subtract 1 from both sides and have 4x=8 then divide both sides by 4 and have x=2 3x+1+x=9 4x+1=9 4x=8 x=2
assuming that V is a typo you would add the x's and have 4x+1=9 then you subtract 1 from both sides and have 4x=8 then divide both sides by 4 and have x=2 3x+1+x=9 4x+1=9 4x=8 x=2
2008-07-09 8:32 am
1)
x^3 + 5x^2 = 6x
x^3 + 5x^2 - 6x = 0
x(x^2 + 5x - 6) = 0
x(x + 6)(x - 1) = 0
x = 0
x + 6 = 0
x = -6
x - 1 = 0
x = 1
∴ x = -6 , 0 , 1
= = = = = = = =
2)
x^2 - 3x = 10
x^2 - 3x - 10 = 0
x^2 + 2x - 5x - 10 = 0
(x^2 + 2x) - (5x + 10) = 0
x(x + 2) - 5(x + 2) = 0
(x + 2)(x - 5) = 0
x + 2 = 0
x = -2
x - 5 = 0
x = 5
∴ x = -2 , 5
= = = = = = = =
3)
x(x - 2)(x + 3) = 0
x = 0
x - 2 = 0
x = 2
x + 3 = 0
x = -3
∴ x = -3 , 0 , 2
x^3 + 5x^2 = 6x
x^3 + 5x^2 - 6x = 0
x(x^2 + 5x - 6) = 0
x(x + 6)(x - 1) = 0
x = 0
x + 6 = 0
x = -6
x - 1 = 0
x = 1
∴ x = -6 , 0 , 1
= = = = = = = =
2)
x^2 - 3x = 10
x^2 - 3x - 10 = 0
x^2 + 2x - 5x - 10 = 0
(x^2 + 2x) - (5x + 10) = 0
x(x + 2) - 5(x + 2) = 0
(x + 2)(x - 5) = 0
x + 2 = 0
x = -2
x - 5 = 0
x = 5
∴ x = -2 , 5
= = = = = = = =
3)
x(x - 2)(x + 3) = 0
x = 0
x - 2 = 0
x = 2
x + 3 = 0
x = -3
∴ x = -3 , 0 , 2
2008-07-09 7:58 am
x^3+5x^2-6x=0 x(x^2+5x-6)=0 x(x+6)(x-1)=0 x=0,-6,or1
x^2-3x-10=0 (x-5)(x+2)=0 x= 5 or -2
x(x-2)(x+3)=0 x=2,0,or -3 x(x^2+x-6)= x^3+x^2-6x
x^2-3x-10=0 (x-5)(x+2)=0 x= 5 or -2
x(x-2)(x+3)=0 x=2,0,or -3 x(x^2+x-6)= x^3+x^2-6x
2008-07-09 7:41 am
Question 1
x³ + 5x² - 6x = 0
x (x² + 5x - 6) = 0
x (x + 6)(x - 1) = 0
x = 0 , x = - 6 , x = 1
Question 2
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = 5 , x = - 2
Question 3
x = 0 , x = 2 , x = - 3
x³ + 5x² - 6x = 0
x (x² + 5x - 6) = 0
x (x + 6)(x - 1) = 0
x = 0 , x = - 6 , x = 1
Question 2
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = 5 , x = - 2
Question 3
x = 0 , x = 2 , x = - 3
2008-07-09 7:39 am
x^3+5x^2=6x
x(x² + 5x -6) = 0
x(x +6)(x -1) = 0
x = 0
x = -6
x = 1
---------------------------
x^2-3x=10
x² - 3x - 10
(x -5)(x + 2) = 0
x = 5
x = -2
---------------------------
x(x-2)(x+3)=0
x = 0
x = 2
x = -3
x(x² + 5x -6) = 0
x(x +6)(x -1) = 0
x = 0
x = -6
x = 1
---------------------------
x^2-3x=10
x² - 3x - 10
(x -5)(x + 2) = 0
x = 5
x = -2
---------------------------
x(x-2)(x+3)=0
x = 0
x = 2
x = -3
收錄日期: 2021-05-01 10:53:33
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