What are the solutions to this equation: 4x^2 - x + 5 = 0?

Quadratic formula:

x = [-b ± √(b² - 4ac)] / 2a

x = [1 ± √((-1)² - 4*4*5)] / 2*4

x = [1 ± √(1 - 80)] / 8

x = (1 ± √-79) / 8

x = (1 ± i√79) / 8

There are, of course, 2 solutions:

1/8 + i√79
1/8 - i√79

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If you don't want a complex answer, simply put down not solutions.

x = [ 1 ± √ (1 - 80) ] / 8
x = [ 1 ± √ (- 79) ] / 8
x = [ 1 ± √ (79 i²) ] / 8
x = [ 1 ± i √79 ] / 8

ax^2+bx+c=y
quad formual is
(-b +/- (sqrt b^2- 4ac))/2a, now plug in
(1 +/-(sqrt 1^2- 4(4*5))/2*4
(1 +/-(sqrt 1 -80))/8
(1 +/- (sqrt -79))/8, now there isnt a sqrt of a negative meaning there are no roots, or the perlabura doesnt touch the x-axis
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Now to find the line of symettry use -b/2a
1/8 and draw an imaginary line at (.125,0)
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After that plug .125 into the equation for x, so
4(.125)^2- .125+5=0 or y
.0625-.125+5=y
-.0625+5=y
4.9375=y, so on that imaginary line plot a point at (.125,4.9375)
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now just plug in x vaules and plot the points, since quadratics are symettrical, just count the spaces in between that point and plot another point the same number of spaces away, but on the other side of the line.
please note for a perlabura to be accurate u MUST plot atleast FIVE points on the coordinate plane

Hope this helps

X equals negative b plus or minus the square root of b squared minus 4 ac all over 2 a. Sing that as a certain song and u will always remmeber the formula.

OK...I tried using the factoring method...doesn't work out...
I used the quadratic formula and arrived with something like this:

x = 1 +/- square root of (don't know how to key in the symbol LOL) -79 all over 8...

since the discriminant (number under the radical sign) is a negative, it is inadmissible meaning it has no real solutions...

it's graph does not intersect with the x-axis!!!!

hope that helps!!!

4x^2 - x + 5 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 4
b = -1
c = 5

x = [1 ±√(1 - 80)]/8
x = [1 ±√-79]/8 (imaginary number)
(no real roots)

4x^2-x+5=0
use the formula x= (-b+_(b^2-4ac)^1/2)/2a
as the determinant comes out to be irrational it is a complex number u study this in class 11.

There are no real solutions, so you have to use the quadratic formula. Have you studied complex numbers yet?
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