factor 9b^2-4 as a difference of two squares?

2008-07-07 7:57 am

回答 (3)

2008-07-07 8:26 am
✔ 最佳答案
a^2 - b^2 = (a + b)(a - b)

9b^2 - 4
= 9b^2 + 6b - 6b - 4
= (9b^2 + 6b) - (6b + 4)
= 3b(3b + 2) - 2(3b + 2)
= (3b + 2)(3b - 2)
2008-07-07 8:05 am
(3b)² - 2²
(3b - 2)(3b + 2)
2008-07-07 8:02 am
(3b-2)x(3b+2)


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