Can someone help?

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x^2+6x+9-9+8=0
(x+3)^2=1
x+3=+-1
x=-2,-4

Solve the equation by factorizing (x^2 + 6x + 8)

(x+4)(x+2)
As 4x + 2x = 6x
and 4 * 2 = 8

Therefore x = -4 , -2

so(a) x=-2, x= -4

x^2 + 6x + 8 = 0
(x + 3)^2 - 1 = 0
(x + 3)^2 = 1
x + 3 = ±√1
x + 3 = ±1

x + 3 = 1
x = 1 - 3
x = -1

x + 3 = -1
x = -1 - 3
x = -4

∴ x = -4 , -2

x^2+6x+9-9+8=0
(x+3)^2=1
x+3=+-1
x=-2,-4

the correct answer is the first one
you can prove this by substituting the values in for x

4-12+8=0
and
16-24+8=0

I don't believe that completing the square would be a good way to solve this problem

a simple factoring will do it
(x+?)(x+?)
what multiplies to give 8 and adds to give six (4 and 2)
(x+4)(x+2)

foil check
x^2+4x+2x+8
x^2+6x+8

so, if (x+4)(x+2)=0, then either x=-4, or x=-2

of course, you can solve this completing the square, but why?

x^2 +6x+8=0
orx^2 +2.3.x+3^2-3^2+8=0
or (x+3)^2-9+8=0
or (x+3)^2=9-8=1
or x+3= +1 OR -1
or x= -3+1 or -3-1
or x= -2 or -4 ans

x² + 6x + 8 = 0
x² + 6x + 9 = 9 - 8
(x + 3)² = 1
x + 3 = ± 1
x = - 2 , x = - 4

(x+4)(x+2)=0

So either x+4=0 or x+2=0

Solving each gives x=-4 or x=-2