(125x^3+8)
Thank you guys :)
How do i factor this?
2008-07-05 5:09 am
回答 (5)
2008-07-05 5:22 am
✔ 最佳答案
Remember that the sum of cubes a³+b³
factors into
(a + b)(a² - ab + b²)
125x³ + 8 = 5³x³ + 2³
= (5x)³ + 2³
= (5x + 2)(25x² - 10x + 4)
2008-07-05 12:17 pm
125x^3 + 8 can be written as
(5x)^3 + 2^3
apply a^3 + b^3 = (a+b)(a^2 - ab + b^2)
which gives [5x+2][25x^2 - 10x + 4]
you got it?
(5x)^3 + 2^3
apply a^3 + b^3 = (a+b)(a^2 - ab + b^2)
which gives [5x+2][25x^2 - 10x + 4]
you got it?
2008-07-05 12:18 pm
It factors into
(5x + 3) (25x^2 -10x +4)
(5x + 3) (25x^2 -10x +4)
2008-07-05 3:22 pm
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
125x^3 + 8
= (5x + 2)(25x^2 - 10x + 4)
125x^3 + 8
= (5x + 2)(25x^2 - 10x + 4)
2008-07-05 12:17 pm
rule is: sum of 2 cubes
a³ + b³ = (a + b)(a² - ab + b²)
so
125x³ + 8
= (5x)³ + 2³
= (5x + 2)((5x)² - (5x)*2 + 2²)
= (5x + 2)(25x² - 10x + 4)
a³ + b³ = (a + b)(a² - ab + b²)
so
125x³ + 8
= (5x)³ + 2³
= (5x + 2)((5x)² - (5x)*2 + 2²)
= (5x + 2)(25x² - 10x + 4)
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