1. Will there be absolutely result of this formula?
1/1+1/2+1/3+1/4+1/5+1/6+1/7......1/(undefined)
2. Any simple formula to calculate this formula
1/1+1/2+1/3+1/4+1/5+1/6+1/7......1/n
e.g. (1+2+3+4+...+n)^2=1^3+2^3+3^3+......n^3
收錄日期: 2021-04-25 22:36:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080703000051KK02224