Please help me to answer the following question /_\
Thank you
The relative abundances of the natural occuring carbon with mass 12 and
carbon with mass 13 are 98.9% and 1.1% respectively. Assuming that there is only 1 stable isotope of H, predict the m/e ratio & relative intensity of
the peak(s) corresponding to the molecular ion of C2H4 (ethane).
F6 Chemistry about mass spectrometry
2008-07-03 2:06 am
回答 (1)
2008-07-03 7:55 am
✔ 最佳答案
There are three peaks:
1st peak:
m/e = 12x2 + 1x4 = 28
(12C12CH4)
Relative intensity = (98.9%)2 = 97.8121%
2nd peak:
m/e = 12 + 13 + 1x4 = 29
(12C13CH4 and 13C12CH4)
Relative intensity = 98.9% x 1.1% x 2 = 2.1758%
3rd peak:
m/e = 13x2 + 1x4 = 30
(13C13CH4)
Relative intensity = (1.1%)2 = 0.0121%
=
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