The sum of two numbers is 65. Five times the smaller number exceeds the larger number by 25. Find the numbers
and if you find it can you explain how you found it i am stumped...
The sum of two numbers is 65?
2008-07-02 6:04 am
回答 (7)
2008-07-02 6:11 am
✔ 最佳答案
Let x be the smaller number. Thus, 65-x is the larger number.5x = 65-x + 25
Solve for x,
6x = 90
x = 15
65-x = 50
So, the two numbers are 15 and 50.
2008-07-02 6:16 am
x + x +25 = 65 therefore
2x+25 = 65 or
2x = 40 (65 -25) Or
x = 20 therefore the numbers x and x+25 are 20 and 45 respectively
2x+25 = 65 or
2x = 40 (65 -25) Or
x = 20 therefore the numbers x and x+25 are 20 and 45 respectively
2008-07-02 6:14 am
x > y
x + y = 65
5y - x = 25
x + y = 65
y = 65 - x
5y = 5(65 - x)
5y - x = 25
5(65 - x) - x = 25
325 - 5x - x = 25
-5x - x = 25 - 325
-6x = -300
x = -300/-6
x = 300/6
x = 50
x + y = 65
50 + y = 65
y = 65 - 50
y = 15
â´ x = 50 , y = 15
x + y = 65
5y - x = 25
x + y = 65
y = 65 - x
5y = 5(65 - x)
5y - x = 25
5(65 - x) - x = 25
325 - 5x - x = 25
-5x - x = 25 - 325
-6x = -300
x = -300/-6
x = 300/6
x = 50
x + y = 65
50 + y = 65
y = 65 - 50
y = 15
â´ x = 50 , y = 15
2008-07-02 6:14 am
Let, smaller one=>x
then larger one=>5x-25
sum=5+x-25 = 6x-25
so, 6x-25=65
=>6x=65+25
=>6x=90
=>x=15
Smaller one=>15
& larger one=>(65-15)=50
then larger one=>5x-25
sum=5+x-25 = 6x-25
so, 6x-25=65
=>6x=65+25
=>6x=90
=>x=15
Smaller one=>15
& larger one=>(65-15)=50
2008-07-02 6:11 am
let x = the smaller no
y = the larger number
x + y = 65
5x - y = 25
add the two
6x = 90
x = 15
x+y =65
15 + y =65
y = 50
y = the larger number
x + y = 65
5x - y = 25
add the two
6x = 90
x = 15
x+y =65
15 + y =65
y = 50
2008-07-02 6:11 am
x = smaller, y = larger
x+y = 65
y +25 = 5x
solve
y = 5x - 25 therefore
x + 5x - 25 = 65
6x = 90
x=15, so y = 50
x+y = 65
y +25 = 5x
solve
y = 5x - 25 therefore
x + 5x - 25 = 65
6x = 90
x=15, so y = 50
2008-07-02 6:09 am
x+y=65
5x = y+25
5x - y = 25
6x = 90
x = 15
y = 50
5x = y+25
5x - y = 25
6x = 90
x = 15
y = 50
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