please factor this?

(3x^2 - 3)^2
= (3x^2 - 3)(3x^2 - 3)
= 3x^2*3x^2 - 3*3x^2 - 3x^2*3 + 3*3
= 9x^4 - 9x^2 - 9x^2 + 9
= 9x^4 - 18x^2 + 9
= 9(x^4 - 2x^2 + 1)
= 9(x^2 - 1)(x^2 - 1)
= 9(x + 1)(x - 1)(x + 1)(x - 1)
= 9(x + 1)^2(x - 1)^2

(3x^2 − 3)^2
= 3(x^2-1)^2
=3(x+1)(x-1)

answer: 3(x+1)(x-1)

3(x+1)(x-1)

9x^4+9

6^=-6 so ...and ^2?...the answer is ^12

[ 3 (x² - 1) ] ²
[ 3 (x - 1)(x + 1) ] ²
9 (x - 1) ² (x + 1) ²

thats already factored. u cant make it n e smaller.. u can expand it though. ure answer will be. 9x^4 - 18x^2 + 9

(3x^2-3)(3x^2-3) That's as far as it'll go without having to resort to imaginary numbers and sh*t.