3y/10-2=y/5+3?

(3y/10)-2 = (y/5) +3

- 3y/10= (y/5) +5

- 3y= 2y +50

y=50

3y - 20 = 2y + 30
y = 50

3y/10 - 2 = y/5 + 3
3y/10 - y/5 = 2 + 3
10(3y/10 - y/5) = 10(5)
3y - 2y = 50
y = 50

3y/10-2=y/5+3
3y/10-y/5=3+2
3y/10-y/5=5
3y-2y/10=5 (The LCM of 10 and 5 comes as 10 in d denominator)
y/10=5
y=50

We start with:

(3y / 10) - 2 = (y / 5) + 3

What we want to do is get rid of those denominators; to do so, we multiply through by 10, the lowest common multiple of 5 and 10 (the denominators):

3y - 20 = 2y + 30

Next, we combine like terms:

y = 50

This is the solution.

y = 50