Solve the quadratic equation 3x² = 33?
回答 (6)
2008-07-01 4:14 pm
✔ 最佳答案
Solutions x = √11 and x = -√11
2008-07-01 4:30 pm
x² = 11
x = ± â 11
x = ± â 11
2008-07-01 4:29 pm
3x^2 = 33
x^2 = 33/3
x^2 = 11
x = 屉11
x = ±3.3166247903554...
x^2 = 33/3
x^2 = 11
x = 屉11
x = ±3.3166247903554...
參考: Square Root Calculator
http://www.math.com/students/calculators/source/square-root.htm
2008-07-01 4:17 pm
hello :)
my answer is:
3x^2=33
3x^2-33=0
3(x^2-11)=0
3=0 is not applicable (extraneous root)
x^2-11=0
x^2=11
x= + and - square root of 11
my answer is:
3x^2=33
3x^2-33=0
3(x^2-11)=0
3=0 is not applicable (extraneous root)
x^2-11=0
x^2=11
x= + and - square root of 11
2008-07-01 4:17 pm
Divide each side by 3:
x² = 11
square root everything:
x = +/- sqrt11
x² = 11
square root everything:
x = +/- sqrt11
2008-07-01 4:15 pm
x^2=11
x=+- sqrt(11)
x=+- sqrt(11)
收錄日期: 2021-05-01 10:45:47
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