What is the solution to s^2-4s+45?

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(s-9)(s+5)=0
s=-5,9

Please put your questions in the form of questions, I'm thinkin you mean "what is the solution to the equation where this expression is equal to zero."

if this were s²-4s-45 = 0
then the solutions would be -5, and 9.

Is that what you meant?,
if not then the solutions are COMplex.
2 ± i√(41)

Well.. if u mean the solution of the equation s^2-4s+45 = 0, then here we go.
The solutions of a quadratic equation of the form a(x^2)+bx+c=0 are given by
(-b±√(b^2-4ac))/2a.
Here a=1,b= -4,c=45
Thus, the solution is:
(4±√(16-180))/2
i.e.,(4±√164i)/2 = 2±√(41)i

I can't solve anything without an equal sign (I doubt anyone can), but s^2 - 4s + 45 = 0 has no real solutions.

Steve

(s+5)(s-9)

Factor it to (s - 9) (s + 5), so s = 9 and -5.

s^2 - 4s + 45
= cannot be factored

If this is equation
s² - 4s + 45 = 0
then
(s - 9)(s + 5) = 0
s = 9 , s = - 5

Factorise this question.
(s-9)(s+5) OR (s+5)(s-9)

If you expand this you will get back to the question. I'm not really sure how to explain how to do that. it's a bit of guess and check. If you do a lot of these questions, you'll get the hang of it.