2 Algebra Questions!!!?

Since all sides of a square are equal, one side being 5n and the other side being n+ 16 must be the same:

5n = n + 16
4n = 16
n = 4

5(4) = 20
(4) + 16 = 20

So n = 4, and the sides of the square are 20 in each.

Let:
n = votes for Connie
t = votes for Cart

We're told that 221 votes were cast, so:

n + t = 221

and told that Connie received 53 more, so:

n = 53 + t

We now have two unknowns and two equations, solve by substitution:

n + t = 221
(53 + t) + t = 221
2t = 168
t = 84

Cart got 84 votes.

n = 53 + t
n = 53 + 84
n = 137

Connie recieved 137 votes.

1)
5n = n + 16
5n - n = 16
4n = 16
n = 16/4
n = 4

5n inches
= 5(4) inches
= 20 inches each side of the square

= = = = = = = =

2)
x = Connie's received votes

x + (x - 53) = 221
x + x - 53 = 221
x + x = 221 + 53
2x = 274
x = 274/2
x = 137

137 - 53
= 84
∴ Connie received 137 votes, Cart received 84 votes.

Question 1
5n = n + 16
4n = 16
n = 4
Length of side = 20 ins.

Question 2
Let Carl have x votes.
Connie has x + 53 votes
x + x + 53 = 221
2x = 168
x = 84

Carl has 84 votes
Connie has 137 votes

5n=n+16
4n=16/5
n=16/20=4/5

n+(n+53)=221
2n+53=221
2n=168
n=84

Connie = 137
Cart=84