someone help me solve this algebra question plz!?

Use order convention. Do brackets first, inside those brackets are more brackets which have to be done first...

Work the brackets from the inside out.

2x - {-3y + [3x - 2(3x - y)]}
= 2x - {-3y + [3x - 6x + 2y]}
= 2x - {-3y - 3x + 2y}
= 2x - {-y - 3x}
= 2x + y + 3x
= 5x + y

2x - {-3y + [3x - 2(3x - y)]}
= 2x - {-3y + [3x - 2*3x + 2*y]}
= 2x - {-3y + [3x - 6x + 2y]}
= 2x - {-3y + 3x - 6x + 2y}
= 2x + 3y - 3x + 6x - 2y
= 2x - 3x + 6x + 3y - 2y
= 5x + y

first multiply -2 by 3x-y
the result will be 2x-{-3y+[3x-6x+2y]}
then multiply1 by 3x-6x+2y
the result will be 2x-{-3y+3x-6x+2y}
then multiply -1 by -3y+3x+6x+2y
the result will be 5x+y

You start from the innermost bracket and you will get the answer. it is 5x+y

2x-{-3y+[3x-2(3x-y)]}=
2x-[-3y+(3x-6x+2y)]=
2x-(-3y-3x+2y)=
2x+y+3x=
5x+y

2x-{-3y+[3x-2(3x-y)]} = 2x-{-3y+[3x-6x+2y]}
= 2x -{-3y + (-3x) + 2y}
= 2x -{-3y -3x +2y}
= 2x -{-y - 3x}
= 2x + y + 3x
= 5x + y

2x - { - 3y + [ 3x - 6x + 2y ] }
2x - { - 3y + [ 2y - 3x ] }
2x - { - y - 3x }
2x + 3x + y
5x + y

Congrgratulations upon using brackets to produce such a clear question.
I can but hope that my answer does justice to the question !