solve by equation?

Answer: x = 80, y = 40
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x * y = 3200

x/y = 2 rewritten: x = 2y Substitute:

2y * y = 3200

2y² = 3200 Divide by 2

y² = 1600 Take square root of both sides:

√y² = √1600

y = 40 Now plug it into the definition for 'x'

x = 2y = 80

x > y
xy = 3200
x/y = 2

x/y = 2
x = 2y

xy = 3200
(2y)y = 3200
2y^2 = 3200
y^2 = 3200/2
y^2 = 1600
y = ±√1600
y = ±40

x/y = 2
x/(±40) = 2
x = ±40(2)
x = ±80

∴ x = ±80 , y = ±40

auaad mein rahna seekh le

given condition is the product of two numbers is 3200

i.e.., ab=3200 ----------(1)

secod condition is the quotient when the larger number is divided by the smaller is 2

let us assume larger number as 'a' and smaller number as 'b'

i.e.., a/b=2
---> a=2b -----(2)

substitute (2) in (1)

ab=3200

2b*b=3200

2b^2=3200

b^2=1600

b=40

now substitute it in equation (2)

i.e.., a=2b;

a=2*40;

a=80

therefore , a=80 and b=40

so, the two numbers are 80,40

(x) (y) = 3200
x/y = 2

x = 2y

2y² = 3200
y² = 1600
y = 40
x = 80

Numbers are 40 and 80

The second answer is right because the numbers can be positive or negative. However, if one of them is positive, the other must be positive as well, and if one of them is negative, the other must be negative as well.

Let the bigger no be x & smaller no. be y.
Then,
x X y =3200 & x / y = 2, Therefore, x = 2y
Therefore, 2y^2 =3200
or, y^2 = 1600
Therefore, y = 40 &
x= 80.

a*b=3200
a/b = 2 so a=2b
so
2b*b=3200
so b^2 = 1600
so b=40 so a=80
.