FACTORISE--> x^3+6x^2+11x+6?

http://www.mathcentre.ac.uk/resources/wo...

Rather that compound factoring, this site demonstrates yet another way to factor cubic equations - "the graphing method". Just plug the equation into your graphing calculator and notice that the graph crosses the x-axis at x=-1, x=-2 and x=-3. Change the signs and the factorization of y = x^3+6x^2+11x+6 becomes (x+1)(x+2)(x+3), easy!

Hope this helps

f(-1) = - 1 + 6 - 11 + 6 = 0
Thus x - (-1) is a factor
Find other factors by using synthetic division.
- 1 | 1 ___6___11___6
__ |____-1____-5__-6
__ | 1___5____6___0

(x + 1)(x² + 5x + 6)
(x + 1)(x + 3)(x + 2)

x^3 + 6x^2 + 11x + 6
= (x^2 + 3x + 2)(x + 3)
= (x + 2)(x + 1)(x + 3)

x^3+6x^2+11x+6=
x^2(x+1)+5x(x+1)+6(x+1)=
(x+1)(x+2)(x+3)

x^3+2x^2+4x^2+11x+6=

x2^(x+2)+4x^2+8x+3x+6=


x^2(x+2)+4x(x+2)+3(x+2)=(x+2)(x^2+4x+3)=

(x+2)(x+1)(x+3)