FACTORISE--> x^3+3x^2-4?
回答 (4)
2008-06-28 6:52 pm
✔ 最佳答案
x^3+2x^2+x^2-4=x^2(x+2)+(x-2)(x+2)=(x+2)(x^2+x-2)=(x+2)(x+2)(x-1)=(x+2)^2(x-1)
2008-06-28 7:06 pm
f (- 2) = - 8 + 12 - 4 = 0
Thus x - (- 2) is a factor.
Find other factors by synthetic division.
- 2 |1___3___0___-4
__ |____-2__-2___4
__ |1___1__ -2___0
(x + 2)(x² + x - 2)
(x + 2)(x + 2)(x - 1)
(x + 2)² (x - 1)
Thus x - (- 2) is a factor.
Find other factors by synthetic division.
- 2 |1___3___0___-4
__ |____-2__-2___4
__ |1___1__ -2___0
(x + 2)(x² + x - 2)
(x + 2)(x + 2)(x - 1)
(x + 2)² (x - 1)
2008-06-28 7:10 pm
x^3 + 3x^2 - 4
= (x^2 + x - 2)(x + 2)
= (x + 2)(x - 1)(x + 2)
= (x - 1)(x + 2)^2
= (x^2 + x - 2)(x + 2)
= (x + 2)(x - 1)(x + 2)
= (x - 1)(x + 2)^2
2008-06-28 6:52 pm
x^2(x-1)+4x(x-1)+4(x-1)=
(x-1)(x^2+4x+4)=
(x-1)(x+2)^2
(x-1)(x^2+4x+4)=
(x-1)(x+2)^2
收錄日期: 2021-05-01 10:43:58
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