Maths For Finance

2008-06-29 7:45 am
Let f (x) = x + 2x2 − 1 and g (x) = √6 − 2x.
(a) Find the domains of f (x) and g (x) .
(b) Find the function f ◦ g (x) and g ◦ f (x) .
(c) Find the inverse of g (x) .
(d) Show that g^−1 (g (x)) = x.

回答 (1)

2008-06-30 1:41 am
✔ 最佳答案
(a) domain for f(x) is all real numbers,
domain for g(x) is x 小於或等於 3, 因為 6 - 2 x不能為負數。

(b) f(g(x)) = ( sqrt( 6-2x ) )+2( sqrt( 6-2x ) )^2-1
= ( sqrt( 6-2x ) )+2( 6-2x )-1
= sqrt( 6-2x ) + 11 - 4x
g(f(x)) = √[ 6 − 2 ( x + 2x^2 − 1 ) ]
= √[ 6 − 2 x + 4x^2 − 2 ) ]
= √[ 4 − 2 x + 4x^2 ) ]

(c) Let y = sqrt ( 6 - 2x )
y^2 = 6 - 2x
2x = 6 -y^2
x = 3 - 1/2 * y^2
g^-1(x) = 3 - 1/2 * x^2

(d) g^-1(g(x))
= 3 - 1/2 * g(x)^2
= 3 - 1/2 * sqrt( 6 - 2x )^2
= 3 - 1/2 *( 6 - 2x )
= 3 - ( 3 - x )
= 3 - 3 + x
= x

P.S.
1. domain 指一個函數的定義域,
入domain外的數字入個function, 就無意思喇!(例如 a part 的開方負數)
2. inverse 係指函數的反函數,係將函數相反的過程。
中一二常常做的主項轉換,就係搵反函數的最佳例子!
參考: 唔明再問我la^^


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