NEED HELP!!! with math question?

2008-06-27 5:28 pm
solving fractional equations I'm not really understanding it completely. I will give a question I already solved the question I just need to know if it's right, and I need help to verify the answer.

3d - 11 = 3 LCD= 8
---- ----
4 2

8(3d) - 8(11)= 8(3)
------ ----
4 2

24d - 22= 12

24d-22+22= 12+22
24d=34

24d = 34
----- -----
24 24

d = 34
-----
24

So my question how do I verify? please show and tell me how to verify a equation with fractions I'm not getting it.


Thanks!!!!!!!!!!!!
更新1:

everybody that's not the correct question it got all messed up. It's 3d- 11/4 = 3/ 2

回答 (5)

2008-06-27 5:57 pm
✔ 最佳答案
You are getting mixed up by trying to do too many things at once. Until you become more experienced, I suggest you do things one at a time !

You need to find the LCD if you are going to combine the two fractions on the left-hand side into one. If you simply want to remove the fractions, do it one at a time.

Just multiply every term by 4 :

4 (3d) / 4 - 4(11) / 2 = 4 x 3, which simplifies to

3d - 22 = 12

Now add 22 to each side :

3d = 34 so d = 34 / 3
------------------------------------

You were lucky here because 4 is the same as 2 x 2, and 2 appeared in the bottom of the second fraction, so you got rid of both in one operation.

If the second fraction were, for example, 11/3, you would have got

12d - 4(11) / 3 = 24 after multiplying by 4,

so then you would have had to multiply throughout by 3 in order to get rid of the second fraction, like this :

3(12d) - 4(11) = 72, or 36d - 44 = 72

---------------------------------------------

Alternatively, if you wanted to combine the two fractions into one,

3d / 4 - 11 / 2 = { 3d - 2 (11) } / 4

So that {3d - 22 } / 4 = 3

Now multiply both sides by 4 to get

3d - 22 = 3 x 4 = 12, as before.

Note that the LCD here is 4, not 8 (because 4 = 2 x 2, so the 2 for the second fraction is included in the 4, you do not need another 2 in there)

Adding fractions is just like adding number fractions, like

1 /2 + 3 / 4 for example, or 2 / 5 + 5 / 6.

If these still give you trouble, perhaps you should try to get someone to go over this sort of problem first, before going on to algebra problems.

-----------------------------------------
2008-06-27 5:31 pm
2008-06-27 6:04 pm
For one thing, the LCD of 2 and 4 is 2 (since 2 divides 4).
Still, though, you made a mistake on your third step. (8*3d)/4=(8/4)*3d=2*3d=6d. Similarly, 8*11/2=44, and 8*3=24.
So you should have 6d-44=24 (or 3d-22=12, or whatever)
Then 6d=68 so d=68/6=34/3.

to check you can just put your solution back in. We had 3d/4-11/2. This is 3*(34/3)/4-11/2=34/4-11/2=17/2-11/2=6/2=3, which is what we were given.
2008-06-27 5:49 pm
To verify you will need to go back to the origional equation
3d / 4 - 11/2 = 3 and substitute the answer you got for "d" every where there is a "d" in the equation. Work this out and make sure that both sides of the = sign are the same. If not, then your answer is not a correct answer or you made a mistake in the verifying process.

on the problem that you did, I would have use 4 for a least common denominator.
4 ( 3d ) / 4 - 4 ( 11) / 2 = 3 ( 4)
this would give
3d - 22 = 12
3d = 34
d = 34 / 3

I am not sure how you came up with 24d - 22 = 12 ???
2008-06-27 5:38 pm
3d/4 - 11/2 = 3
4(3d/4 - 11/2) = 4(3)
12d/4 - 44/2 = 12
3d - 22 = 12
3d = 12 + 22
3d = 34
d = 34/3 (11 1/3)


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