5x + 6y =2, 10x + 12y = 4 Solve by elimination method?
回答 (5)
2008-06-27 5:39 am
✔ 最佳答案
Multiply the first equation by -2, then add the first to the second, this will cancel out the y's, then you can solve for x:-10x - 12y = -4
10x + 12y = 4
0x + 0y = 0
These two equations are identicle lines, so there are infinately many solutions.
2008-06-27 2:40 pm
5x + 6y = 2
10x + 12y = 4
5x + 6y = 2
2(5x + 6y) = 2(2)
10x + 12y = 4
...10x + 12y = 4
-- 10x + 12y = 4 (subtraction)
------------------------
0x + 0y = 0
(they are the same line)
(many solutions)
10x + 12y = 4
5x + 6y = 2
2(5x + 6y) = 2(2)
10x + 12y = 4
...10x + 12y = 4
-- 10x + 12y = 4 (subtraction)
------------------------
0x + 0y = 0
(they are the same line)
(many solutions)
2008-06-27 12:48 pm
the equations are exactly the same
there isn't one exact answer to this system
there isn't one exact answer to this system
2008-06-27 12:40 pm
10x + 12y = 4 ---> eq1 multiplied by 2
10x + 12y = 4
The system has infinite solutions.
10x + 12y = 4
The system has infinite solutions.
2008-06-27 12:40 pm
you can multiply the first equation by -2 and then add the resulting equation to the second equation. i.e.:
-2(5x + 6y) = -2(2)
-10x -12y = -4. adding this to the second equation you get 0 = 0, which implies that these are exactly the same equation, and there are infinitely many solutions.
-2(5x + 6y) = -2(2)
-10x -12y = -4. adding this to the second equation you get 0 = 0, which implies that these are exactly the same equation, and there are infinitely many solutions.
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