Please answer precisely and clearly with steps.Thanks!
圖片參考：http://hk.geocities.com/qs2487/Definite_Integrals.jpg
Integration Problem
2008-06-26 8:18 am
回答 (2)
2008-06-26 9:22 am
✔ 最佳答案
it is extremely easySince from the range of integration, we can se that
0＜=t＜=x
So ∫t^(2k+1)/(1-t^2) dt
＜=1/(1-x^2)∫t^(2k+1) dt
2008-06-26 01:22:33 補充：
x 應該小於1
2008-06-26 17:20:10 補充：
我要強調x是constant
2008-06-26 5:43 pm
Take differentiation on both sides, by fundemental theorem of calculus, we know that we now need to prove
(x2k+1)/(1-x2)<=(1/1-x2)(x2k+1)
In which LHS=RHS and so the inequality stands
(x2k+1)/(1-x2)<=(1/1-x2)(x2k+1)
In which LHS=RHS and so the inequality stands
收錄日期: 2021-04-26 13:05:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080626000051KK00050