can someone solve this equation please show work?

x^3/2 = 125
x^3/2 * 2/3 = 125^ 2/3
x = 25

Here's Why
In exponents if you have a fraction, such as 3/2, you do take the number and can convert it into a radical. The denominator is the index, and the numerator is the exponent inside the radical. So for x^3/2 in radical form, it would be the square root of 3. For x^4/3 in radical form, it would be the cubic root of x^4

x3/2 = 125 => pow(square(x),3) = pow(5,3) => square(x) = 5 =>x=25 unique solution.

x^3/2 = 125
x^3 = 2(125)
x^2 = 250
x = ±√250
x = ±15.81 (approx.)

do you mean 3x/2=125? if so, multiply both sides by 2. then you have 3x=250. then divide both sides by 3. you'll have x=83.33. hope this helps.

x3/2 = 125
i no really know what is your question. so i assumed that the question is x^3/2 = 125
x^3 = 250
x = 6.30

is that :

x^(3/2) = 125

If so, you want to take both sides to the same power such that you end up with x^1 at the end.

The rule here is:

(a^x)^y = a^(xy)

So if you take both sides to the (2/3) power, you'll end up with x^1, and can solve:

(x^(3/2))^(2/3) = 125^(2/3)
x^((3/2)(2/3)) = ³√(125²)
x = ³√(15625)
x = 25

Is this x^(3/2) = 125?
Then (x^(3/2))^(2/3) = 125^(2/3)
x = (125^(1/3))^2 = 5^2=25

I assume you mean x^(3/2) = 125
read as x raised to the power (3/2) is equal to 125

=> x = (125)^(2/3) = 25