solve each equation for x?

4^(x+1) = 4^(3x-5)
therefore
(x + 1) = (3x – 5)
2x = 6
x = 3

8^2x = 8^(3x-1)
therefore
2x = 3x -1)
x = 1

10^6x = 100^(x+6)
10^6x = 10^2^(x+6)
10^6x = 10^(2x+12)
6x = (2x+12)
4x = 12
x = 3
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eq1=> 4^(x+1)=4(^3x-5)
=> (x+1)log4=(3x-5)log4
=> x+1=3x-5
=> 3x-5=x+1
=> 3x-x=1+5
=> 2x=6
=> x=3




8^2x= 8(^3x-1)
2x=3x-1
2x-3x=-1
-x=-1
x=1


10^6x= 100(^x+6)
10^6x=(10^2)^(x+6)
10^6x=10^(2(x+6))
6x=2(x+6)
6x=2x+12
4x=12
x=3

1)
4^(x + 1) = 4^(3x - 5)
x + 1 = 3x - 5
x - 3x = -1 - 5
-2x = -6
x = -6/-2
x = 3

2)
8^2x = 8^(3x - 1)
2x = 3x - 1
3x - 2x = 1
x = 1

3)
10^6x = 100^(x + 6)
100^3x = 100^(x + 6)
3x = x + 6
3x - x = 6
2x = 6
x = 6/2
x = 3

Questions are incorrectly presented.
Should be :-

Question 1
4^(x + 1) = 4^(3x - 5)
x + 1 = 3x - 5
6 = 2x
x = 3

Question 2
8^(2x) = 8^(3x - 1)
2x = 3x - 1
x = 1

Question 3
10^(6x) = 100^(x + 6)
10^(6x) = 10^(2x + 12)
6x = 2x + 12
4x = 12
x = 3

Hate to say it, but your presentation could be better !
Good luck anyway.