以下是小兒中一的數學,
請問公式如何計算?
書本有答案,
但沒有步驟.
(3x+5)/4 - (2x+2)/3 = 1
中一數學 (5)
2008-06-25 2:15 am
回答 (6)
2008-06-29 2:23 am
(3x+5)/4 - (2x+2)/3 = 1
(3x+5)3 - (2x+2)4 = 1(12)
9x+15-8x-8=12
x=5
(3x+5)3 - (2x+2)4 = 1(12)
9x+15-8x-8=12
x=5
2008-06-28 1:07 pm
(3x 5)/4 - (2x 2)/3 = 1
首先要通分母, 所以要乘12
(3x 5)/4*12 - (2x 2)/3 *12 = 1*12
3(3x 5) -4 (2x 2) = 12
9x 15 -8x-8 = 12
9x -8x 15-8 = 12
x 7 = 12
x = 12-7
x = 5
首先要通分母, 所以要乘12
(3x 5)/4*12 - (2x 2)/3 *12 = 1*12
3(3x 5) -4 (2x 2) = 12
9x 15 -8x-8 = 12
9x -8x 15-8 = 12
x 7 = 12
x = 12-7
x = 5
參考: myself
2008-06-25 2:41 am
(3x+5)/4 - (2x+2)/3 = 1
(9x+15)/12-(8x-8)12 = 1
( 9x-8x+15-8)/12 =1
(x+7)/12 =1
x+7 = 1x12
x+7 =12
x =12-7
x = 5
(9x+15)/12-(8x-8)12 = 1
( 9x-8x+15-8)/12 =1
(x+7)/12 =1
x+7 = 1x12
x+7 =12
x =12-7
x = 5
2008-06-25 2:39 am
x=5 ar!!
2008-06-25 2:31 am
(3x+5)/4 - (2x+2)/3 = 1
(3x+5)/4乘12- (2x+2)/3乘12=1 (因為要通分母)
9x+15-8x-8=1
x=9-15
x=-6
再代x=-6入去9x+15-8x-8=1
9乘(-6)+15-8乘(-6)-8=1
所以x=6是正確的
(3x+5)/4乘12- (2x+2)/3乘12=1 (因為要通分母)
9x+15-8x-8=1
x=9-15
x=-6
再代x=-6入去9x+15-8x-8=1
9乘(-6)+15-8乘(-6)-8=1
所以x=6是正確的
2008-06-25 2:20 am
(3x+5)/4 - (2x+2)/3 = 1
(3x+5) - (2x+2)/3*4 = 1*4
(3x+5) - (8x+4)/3 = 4
(3x+5)*3 - (8x+4) = 4*3
(9x+15) - (8x+4)=12
9x+15-8x-4=12
9x-8x=12-15+4
x=1
(3x+5) - (2x+2)/3*4 = 1*4
(3x+5) - (8x+4)/3 = 4
(3x+5)*3 - (8x+4) = 4*3
(9x+15) - (8x+4)=12
9x+15-8x-4=12
9x-8x=12-15+4
x=1
參考: 我
收錄日期: 2021-04-13 15:44:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080624000051KK02043