solve(3x-5)/(x+5)=1?

(3x-5)/(x+5)=1
multiply each side by (x+5):
3x - 5 = x + 5
evaluate:
2x = 10
divide:
x = 5

(3x - 5) / (x + 5) = 1

Multiply both sides by (x + 5):

(3x - 5) = (x + 5)

Remove brackets:

3x - 5 = x + 5

Add 5 to both sides:

3x = x + 10

Subtract x from both sides:

2x = 10

Divide both sides by 2:

x = 5

all you have to know to solve these problems, is that whatever you do to one side of the problem, you must also do to the other side. 3(x-3)=5(1.5+x) (3*x + 3*-3) = (5*1.5 + 5*x) 3x + -9 = 7.5 + 5x 3x + -9 + 9 - 5x = 7.5 + 9 + 5x - 5x 3x - 5x = 7.5 + 9 -2x = 16.5 -2x/2 = 16.5/-2 x = (-16.5)/2 x = -8.25 *****I hope that this helps some!!!! Good Luck!!!!*****

3x - 5 = x + 5
2x = 10
x = 5

(3x - 5)/(x + 5) = 1
3x - 5 = 1(x + 5)
3x - 5 = x + 5
3x - x = 5 + 5
2x = 10
x = 10/2
x = 5

Multiply both sides by (x + 5)
To get 3x - 5 = x + 5
(When you multiply a fraction by it's denominator, it gives you the numerator.
ie. a/b * b
= a/b * b/1
= ab/b
b's cancel out to leave a/1 = a)

Now just solve like normal.
3x - 5 = x + 5
3x - x = 5 + 5 (It should already be obvious that x is 5 :))
2x = 10
x = 5

(3x-5)/(x+5)=1

(3x-5) = (x+5)

3x - x = 5+5

2x = 10
x=5

x=5

(3x-5)/(x+5)=1...multiply both sides by (x+5)
3x-5 = 1(x+5)
3x-5 = x+5...bring the x to the left and the -5 to the right
3x-x = 5+5
2x = 10
x=5

x=5