ordered pair using substitution 2x - 3y = -9, x + 2y = 13?

2x-3y=-9....(1)
x+2y=13....(2)

(2)x2:
2x+4y=26...(3)

(1)-(3):

-3y-4y=-9-26
-7y=-35
y=<5>

when y=5, sub 5 into (1).

2x-3(5)=-9
2x=6
x=<3>

approach a million y = a million - 4x 6x + 2 - 8x = - 2 4 = 2x x = 2 y = a million - 8 y = - 7 y = - 7 x = 2 , y = - 7 approach 2 Qu a million 6x + 2y = - 2 -8x - 2y = - 2---------upload -2x = - 4 x = 2 12 + 2y = - 2 2y = - 14 y = - 7 x = 2 , y = - 7 different questions are carried out in the comparable way----over to you !

2(13 - 2y) - 3y = - 9
26 - 4y - 3y = - 9
- 7y = = - 35
y = 5

x + 10 = 13
x = 3

x = 3 , y = 5

2x-3y = -9 --------1
x+2y = 13 --------2
__________

[ x=13-2y] from 2

so
2(13-2y) - 3y = -9

26 - 4y - 3y = -9

26 +9 =4y + 3y
35=7y
then y=5
putting y in eq. 2

result

x + (5*2) = 13
x= 3

so y=5 & x =3

x+2y=13
-2y -2y
x=13-2y

2(13-2y)-3y=-9
26-7y=-9
-26 -26
-7y=-35
y=5

then plug y=5 into 2x-y=-9 to find x

2x - 3y = -9
x + 2y = 13

2x - 3y = -9
3y = 2x + 9
y = (2x + 9)/3
2y = 2(2x + 9)/3

x + 2y = 13
x + (4x + 18)/3 = 13
3[x + (4x + 18)/3] = 3(13)
3x + 4x + 18 = 39
7x = 39 - 18
7x = 21
x = 21/7
x = 3

x + 2y = 13
3 + 2y = 13
2y = 13 - 3
2y = 10
y = 10/2
y = 5

∴ x = 3 , y = 5

2x - 3y = -9,

x + 2y = 13
2x + 4y = 26
2x = -4y + 26

substitute 2x to 1st equation
2x - 3y = -9,
-4y + 26 - 3y = -9,
-7y + 26 = -9
-7y = -9 -26
-7y = -35
y = 5

2x - 3y = -9
2x - 3(5) = -9
2x -15 =-9
2x = -9 + 15
2x = 6
x =3

2x - 3y = -9..........(1)
x + 2y = 13..........(2)

multiply equation(2) by -2
-2x - 4y = -26..........(3)

add equation(1)&(3)
2x - 3y = -9..........(1)
-2x - 4y = -26........(3)

-7y = 35
y = -5

subsitute with the value of y in equation(1) to find x
2x - 3(-5) = -9..........(1)
2x + 15 = -9
2x = -9-15
2x = -24
x= -12

so the solution is ( -12, -5)