The sum of three consecutive even integers is 204. Find the integers.?
How in th heck do I do this?
ix
回答 (11)
✔ 最佳答案
x+ x+2 + x+4=204
3x+6=204
x+2=68
x=66
66, 68, 70
Hi,
Even integers are always 2 apart, so if x is the smallest even integer, then the next 2 even integers are x + 2 and x + 4.
If their sum is 204, then:
x + x+2 + x+4 = 204
3x + 6 = 204
3x = 198
x = 66
x+2 = 68
x+4 = 70
The 3 numbers are 66, 68, and 70. <==ANSWER
I hope that helps!! :-)
Let the numbers be x, x+2 and x+4
( x ) + ( x + 2) + ( x + 4) = 204
3 x + 6 = 204
3 x = 204 - 6 = 198
x = 198/3 = 66
Hence the three nos are 66, 68, and 70
The integers are: 66, 68, 70.
Soln:
let the numbers be (x-2), x, (x+2)
then..
(x-2)+ x+ (x+2)=204
solving for x gives x=68.
Consecutive numbers will be close to each other, hence they will be close to 204/3. This comes out just under 70. The three numbers are 66, 68, 70
2x + (2x + 2) + (2x + 4) = 204
6x + 6 = 204
6x = 198
x = 33
2x = 66
Integers are 66 , 68 , 70
66 + 68 + 70
= 204
â´ the three consecutive even integers are 66 , 68 , 70.
Let x = be the first integer
x + 2 = the next integer
x + 4 = the third integer
x + x+ 2 + x + 4 = 204
x+x+x = 204 -2 - 4
3x = 198
x = 66
then, x + 2 = 68
and, x + 4 = 70
X+(X+2)+(X+4)=204
X is the small #....
3X+6=204
3x=198
x=66
so the answers are 66, 68, 70
070+
068=
138+
066=
204
收錄日期: 2021-05-01 10:38:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080622061209AA9NvBE
檢視 Wayback Machine 備份