Solve the equation below. Show your work and explain your steps.
Use ^ to indicate a power and "sqrt" to indicate a radical.
x^2 - 25 = 0?
2008-06-20 7:06 pm
回答 (8)
2008-06-20 7:11 pm
✔ 最佳答案
x^2 - 25 = 0x^2 = 25
x = ±√25
x = ±5
2008-06-21 2:11 am
Factor it. Remember that this is in ax^2 + bx + c = 0 form. Find two integers that multiply to equal c, but add to equal b. In this, c = -25 and b = 0, so the two integers are 5 and -5:
x^2 - 25 = 0
(x - 5) (x + 5) = 0
Now separate the parentheses into different equations and solve for x:
x - 5 = 0
x = 5
x + 5 = 0
x = -5
Answer: x = -5, 5
x^2 - 25 = 0
(x - 5) (x + 5) = 0
Now separate the parentheses into different equations and solve for x:
x - 5 = 0
x = 5
x + 5 = 0
x = -5
Answer: x = -5, 5
2008-06-25 2:10 am
x² = 25
x = ± 5
x = ± 5
2008-06-21 2:24 am
x^2-25=0
x^2=25
x=5
x^2=25
x=5
2008-06-21 2:23 am
why did you answer this question?
x^2 - 25 = 0
x^2 = -(-25)
x^2 = 25
so:
x = +5 and -5
x^2 - 25 = 0
x^2 = -(-25)
x^2 = 25
so:
x = +5 and -5
2008-06-21 2:15 am
its a perfect square
(x+5)(x-5)=0
therefore
x=-5, x=5
(x+5)(x-5)=0
therefore
x=-5, x=5
2008-06-21 2:12 am
5
2008-06-21 2:12 am
x^2 - 25 = 0
x^2 = 25
x = +-sqrt25
x = +-5
x = 5 Or x = -5
x^2 = 25
x = +-sqrt25
x = +-5
x = 5 Or x = -5
收錄日期: 2021-05-01 22:49:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080620110601AABuhmS