can some one plz solve this 2x^2 = 16?

2008-06-20 6:50 pm

Solve the equation below. Show your work and explain your steps.
Use ^ to indicate a power and "sqrt" to indicate a radical.

回答 (10)

[匿名]

2008-06-20 6:54 pm

✔ 最佳答案

2x^2 - 16 = 0

2(x^2 - 8) = 0

so solution is when x^2 = 8

so x = sqrt(8) = +/- 2sqrt(2)

參考: Note that sqrt gives both a positive and negative solution (although a calculator won't tell you this). This is because (-2)(-2) = 4 and (2)(2) = 4 also. lol I made a mistake and corrected but people are so quick on here I got thumbed down before I could fix it. Even though it took me 10 seconds to fix it. Damn you people are quick to judge, lol :)

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[匿名]

2008-06-21 1:53 am

2xÂ² = 16
xÂ² = 8
x = Â±2â2

You should be getting the point by now. If your not, I really feel sorry for you.

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[匿名]

2008-06-21 1:56 am

2x^2 =16.

x^2 = 16/2 =8.
x= square root of 8.

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llaffer

2008-06-21 1:53 am

2xÂ² = 16

Divide by 2:

xÂ² = 8

Square root of both sides:

x = Â±â8

simplify the radical:

x = Â±â(4 * 2)
x = Â±2â2

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Como

2008-06-22 2:09 am

xÂ² = 8
xÂ² = (4) (2)
x = Â± 2 â2

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[匿名]

2008-06-21 3:48 pm

-4

參考: just found out on a dammm caCULATOR

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[匿名]

2008-06-21 1:58 am

Divide both sides by 2

2x^2/2 = x^2 = 16/2 = 8

sqrt(8) = sqrt(4*2) = sqrt(4)*sqrt(2) = 2*sqrt(2)

Taking the square root of both sides

x = 2*sqrt(2) and x = -2*sqrt(2)

參考: Longtime college math teacher

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An ESL Learner

2008-06-21 1:57 am

2x^2 = 16
x^2 = 16/2
x^2 = 8
x = Â±â8
x = Â±2.82 (approx.)

參考: Square Root Calculator http://www.math.com/students/calculators/source/square-root.htm

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[匿名]

2008-06-21 1:55 am

x^2=8 x=+-sqrt(8)=+-2sqrt(2)

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[匿名]