3x^2 = -9x?
Solve the equation below. Show your work and explain your steps.
Use ^ to indicate a power and "sqrt" to indicate a radical.
回答 (14)
✔ 最佳答案
3x² = -9x
3x² + 9x = 0
Factor out a 3x:
3x(x + 3) = 0
3x = 0 and x + 3 = 0
x = 0 and x = -3
Answer is :
x = -3, 0
3x^2 + 9x = 0
3x(x + 3) = 0
x(x+3) = 0
x =0 or x = -3
3x^2 = -9x
3x² + 9x = 0
3x(x + 3) = 0
x= 0 or -3 or 3i^2;
where 'i' is an imaginary quantity and i^2 is -1.
參考: 16 yrs of exp...
Clearly, if x = 0, we have a solution.
If x is not zero, we can divide both sides by x to get
3x = -9
Divide both sides by 3
3x/3 = x = -9/3 = -3
Two solutions
x = 0 and x = -3
參考: Longtime college math teacher
3x^2 = -9x
3x^2 + 9x = 0
3x(x + 3) = 0
(x + 3) = 0
x = -3 OR x = 0
This is a quadratic: ax^2 + bx + c
where c = 0
3x^2 + 9x = 0
3x(x + 3) = 0
So, x = 0, x = -3
3x^2 = -9x
3x^2 + 9x = 0
3x(x + 3) = 0
3x = 0
x = 0/3
x = 0
x + 3 = 0
x = -3
∴ x = 0 , -3
3x^2 = -9x
3x^2 + 9x = 0 (add 9x to both sides)
3x(x + 3) = 0 (extract 3x as a common factor)
3x = 0 or x+3 = 0
x=0 or x=-3
3x² = -9x
Bring over the -9x to the left:
3x² + 9x = 0
Factor out a 3x:
3x(x + 3) = 0
Now from this you have that x = 0 or x = -3.
Hope this helps!
Hi,
3x^2 = -9x
3x² = -9x
3x² + 9x = 0
3x(x + 3) = 0
3x = 0
x = 3 <== ANSWER
x + 3 = 0
x = -3 <==ANSWER
I hope that helps!! :-)
收錄日期: 2021-05-01 10:38:02
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