find the pattern
2,0,-2,-4,-6..........................
maths問題!!!急!!!!!!!急!!!!!!!!!!!!!!!
2008-06-20 9:03 pm
回答 (5)
2008-06-20 9:34 pm
✔ 最佳答案
As the difference of any two successive members of the pattern is a constant (－2), the pattern is an arithmetic progression or arithmetic sequence.The initial term of the arithmetic progression is 2 and the common difference of successive members is －2. Therefore, the nth term of the sequence is given by
a(n)＝2＋(n－1)(－2)＝4－2n
where n＝1,2,3,...
2008-06-21 3:15 am
2-2=0
0-2=-2
-2-2=-4
-4-2=-6
-6-2=-8
......
希望可以帮到你拉!
0-2=-2
-2-2=-4
-4-2=-6
-6-2=-8
......
希望可以帮到你拉!
2008-06-21 2:36 am
有絛FORMULA你用既
T(n)=a+d(n-1)
then a=the first number=2
d=-2
T(n)=2-2(n-1)
=4-2n
T(n)=a+d(n-1)
then a=the first number=2
d=-2
T(n)=2-2(n-1)
=4-2n
參考: My self
2008-06-20 9:13 pm
可以睇到係每個數減2
由於第一個TERM係2, 所以PATTERN 可以用一條式總結: 2+(-2)(n-1)
由於第一個TERM係2, 所以PATTERN 可以用一條式總結: 2+(-2)(n-1)
2008-06-20 9:12 pm
T(1)2=2-2x(1-1)
T(2)=0=2-2x(2-1)
T(3)=-2=2-2x(3-1)
T(4)=-4=2-2x(4-1)
T(5)=-6=2-2x(5-1)
T(n)=2-2(n-1)=2-2n+2=4-2n
T(2)=0=2-2x(2-1)
T(3)=-2=2-2x(3-1)
T(4)=-4=2-2x(4-1)
T(5)=-6=2-2x(5-1)
T(n)=2-2(n-1)=2-2n+2=4-2n
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