How do you do this math problem (3y^2)^3?

27y^6

its 27y^6

(3y^2)^3=3^3*(y^2)^3=27*y^6

to the power three means =

( 3Y^2)^3 = { 3^3 *( Y^2)^3 } = 27 * Y^6 = 27Y^6

y^2
*3
all raised to the 3rd power

or ((y^2)*3)^3


Please Excuse My Dear Aunt Sally or
Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction

27y^8
(3*3*3)(y^2)^3
27(y^2)^3
27y^8

(3y^2)^3
= (3^3)[y^(2 * 3)]
= (27)[y^6]
= 27y^6

(3y²) (3y²) (3y²) = 27 y^6

To simplify this expression you use one of the rules of indices:

(ax^n)^m = x^m*a^(a*m)

Hence

(3y^2)^3

= 3^3y^(2*3)

= 27y^6

Simplified, the answer is:
27y^6 Explained:
(3 times 3 times 3) = 27 and by the rules of exponents, multiply the power of 2 by the power of 3 which the entire term is raised to = (2 times 3) = 6; therefore, 27y^6

27y^6


make it 3 x 3 x 3
y^2 x y^2 x y^2


The x is multiplication