Evaluate 2x^-1 y^3 If x = 2 And y = -1?

Simple substitution and order of operations.

2x^(-1)y^3
2*(2)^(-1)*(-1)^3
2^(-1) = 1/2
(-1)^3 = -1
2(1/2)(-1) = -1

2^-1 is 1/2
2 times this is 1
then you have (-1)^3=-1
so you have 1 times -1 is -1
hence answer B

8x^3+y^3 = (2x)^3 + y^3 Now we may be able to element that as a sum of cubes = (2x + y)(4x^2 - 2xy + y^2) Now, (2x+y)^2 = 4x^2 + 4xy + y^2, so our 2d element is (2x+y)^2 - 6xy = (2x+y)((2x+y)^2 - 6xy) = 12(12^2 - 6 * 10) = 12(one hundred forty four-60) = 1008

(2 / x) y³
(2 / 2) (-1)
- 1
OPTION B

2x^-1y^3
= 2(2^-1)(-1^3)
= 2(1/2)(-1)
= (2/2)(-1)
= 1(-1)
= -1
(answer B)

2x^-1y^3 when x= 2 y= -1

2(2)^-1(-1)^3=

2^-1= 0.5 and -1^3= -1
hence:

2(0.5)(-1)= -1

2(2)^-1 (-1)^3= -1

The first term is equal to 2/2 which equals 1. And the second is equal to -1.

are you in summer school now or something i am already out of school.

Plug in 2 wherever it says x and plug in -1 wherever it says y and do it yourself.

2(2^-1)(-1^3)
2(1/2)(-1)
1(-1)
=-1
B