solve 5x-3y=7 and x+6y= -4?

2008-06-19 6:53 pm

回答 (4)

2008-06-19 7:06 pm
✔ 最佳答案
Solve second equation for x.

x=-6y-4.

Plug it into x in the first equation.

5(-6y-4)-3y=7 and solve for y.

-30y-20-3y=7
-20=33y=7
33y=-13
y=-.39393939

Plug in y to find x

x+6(-39393939)=-4
x-2.36363636=-4
x=-1.63636363.

Try it

(-1.63636363)+6(-.39393939)=-4.

Good job.
2008-06-20 2:14 am
5x - 3y = 7
x + 6y = -4

(5x - 3y) x 2 = 7 x 2
10x - 6y = 14
(10x - 6y) + ( x + 6y) = 14 + (-4)
11x = 14 - 4
11x = 10
x = 10/11

x + 6y = -4
(10/11) + 6y = -4
6y = -4 - (10/11)
6y = (-44/11) - (10/11)
6y = -54/11
y = (-54/11) / 6
y = -9/11

x = 10/11
y = -9/11
2008-06-20 2:13 am
10x - 6y = 14
x + 6y = - 4------ADD

11x = 10
x = 10/11

10/11 + 6y = - 4
6y = - 44/11 - 10/11
6y = - 54/11
y = - 9/11

x = 10/11 , y = - 9/11
2008-06-20 2:03 am
5x - 3y = 7 (solve using substitution)
x + 6y = -4

5x - 3y = 7
3y = 5x - 7
6y = 2(5x - 7)

x + 6y = -4
x + 2(5x - 7) = -4
x + 10x - 14 = -4
x + 10x = -4 + 14
11x = 10
x = 10/11

5x - 3y = 7
5(10/11) - 3y = 7
50/11 - 3y = 7
3y = 50/11 - 7
3y = 50/11 - 77/11
3y = -27/11
y = (-27/11)/3
y = -9/11

∴ x = 10/11 , y = -9/11


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