更新1:
HAHA nevermind, i remembered, everything to the power of 0 is 1.. sry
solve 99^x = 1 and how do i do it?
回答 (8)
2008-06-19 6:01 pm
✔ 最佳答案
Take the base 99 logarithm of both sides of the equation to remove the variable from the exponent. log99(99^x)=log99(1)
The left-hand side of the equation is equal to the exponent of the logarithm argument because the base of the logarithm equals the base of the argument.
x=log99(1)
The logarithm of 1 for any base is 0.
x=(0)
Remove the parenthesis around the expression 0.
x=0 <---answer
2008-06-20 1:13 am
x log 99 = log 1
x log 99 = 0
x = 0
x log 99 = 0
x = 0
2008-06-20 1:08 am
Just by looking at it, an experienced math student will tell you any power to 0 is 1. So x is 0.
To prove it mathematically,
99^x = 1
log(99^x) = log(1)
x log(99) = log(1)
x= log (1) / log (99)
x=0
From the third line, it's already apparent that x=0 since log(1)=0.
To prove it mathematically,
99^x = 1
log(99^x) = log(1)
x log(99) = log(1)
x= log (1) / log (99)
x=0
From the third line, it's already apparent that x=0 since log(1)=0.
2008-06-20 12:51 am
n^0 = 1
99^x = 1
99^x = 99^0
x = 0
99^x = 1
99^x = 99^0
x = 0
2008-06-20 12:50 am
x=0
Anything raised to power 0 is 1.
Anything raised to power 0 is 1.
2008-06-20 12:51 am
99^0 =1
2008-06-20 12:51 am
That's okay... I forget that all the time haha.
2008-06-20 12:50 am
yeah!
You are right!
You are right!
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