Assume y varies inversely as x. If y = -32 when x = 2, what is x when y = 4?
回答 (11)
2008-06-17 3:32 pm
✔ 最佳答案
y = n/x-32 = n/2
n = -64
4 = -64/x
x = -64/4
x = -16
2016-10-18 2:14 pm
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2008-06-17 4:07 pm
x = n/y
2 = n/-32
n = 2(-32)
n = -64
When y = 4, x equals:
x = n/y
x = -64/4
x = -16
2 = n/-32
n = 2(-32)
n = -64
When y = 4, x equals:
x = n/y
x = -64/4
x = -16
2008-06-17 3:44 pm
When y is -32, x=2
So when y is 4, x will be 2/-32 x 4
= - 1/4
So when y is 4, x will be 2/-32 x 4
= - 1/4
2008-06-17 3:37 pm
x1y1=x2y2
-> -32 x 2 = 4x
x = -64/4
= -16
-> -32 x 2 = 4x
x = -64/4
= -16
2008-06-17 3:35 pm
If y varies inversely as x, it means that y = k/x where k is some constant.
To find the constant, substitute x and y.
-32 = k / 2
k = -64
When y = 4,
x = k/y = -64/4 = -16
The answer is -16.
Note: You could have found this directly by computing
(-32)(2) / 4 = -64 / 4 = -16
If y varied directly as x, the answer would be
(4)(2) / (-32) = -1/4
To find the constant, substitute x and y.
-32 = k / 2
k = -64
When y = 4,
x = k/y = -64/4 = -16
The answer is -16.
Note: You could have found this directly by computing
(-32)(2) / 4 = -64 / 4 = -16
If y varied directly as x, the answer would be
(4)(2) / (-32) = -1/4
參考: High school
2008-06-17 3:35 pm
y varies inversely as x.
y=k/x, where k is a constant
-32 = k / 2
k=-64
So, y=-64/x
when y=4
4 = -64/x
4x=-64
x=-16
y=k/x, where k is a constant
-32 = k / 2
k=-64
So, y=-64/x
when y=4
4 = -64/x
4x=-64
x=-16
2008-06-17 3:35 pm
-32/2=4/x
-16/1=4/x
-16x=4
x=-4/16
x= -1/4
-16/1=4/x
-16x=4
x=-4/16
x= -1/4
2008-06-17 3:33 pm
y proportional to 1/x
y=K(1/x), K being the constant needed to make the
change from "proportional to" to "equals".
y= -32, x=2, then
-32=K/2, and K= -64
When y=4,
4= -64/x
4x= -64
x= -16
y=K(1/x), K being the constant needed to make the
change from "proportional to" to "equals".
y= -32, x=2, then
-32=K/2, and K= -64
When y=4,
4= -64/x
4x= -64
x= -16
2008-06-17 3:32 pm
-1/4
收錄日期: 2021-05-01 10:38:56
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